Motion problems use one formula, $d = rt$: distance equals rate times time. You have used rates like miles per hour when converting units, and you can write equations from words. Here the two skills meet.
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Worked examples
Ejemplo resuelto: Opposite directions
- Let $t$ be the time in hours. East: rate $50$, distance $50t$. West: rate $30$, distance $30t$.
- Moving apart, the distances add: $50t + 30t = 160$.
- $80t = 160$, so $t = 2$.
- Check: $100 + 60 = 160$ miles.
Respuesta: After $2$ hours.
Ejemplo resuelto: Catching up
- Let $t$ be the car's time in hours. The truck has driven one hour longer: $t + 1$.
- Truck: $45(t + 1)$. Car: $60t$. Same direction, so at the moment it catches up the distances are equal: $60t = 45(t + 1)$.
- Distribute: $60t = 45t + 45$. Subtract $45t$: $15t = 45$, so $t = 3$.
- Check: the car goes $180$ miles; the truck goes $45 \cdot 4 = 180$ miles.
Respuesta: $3$ hours.
Ejemplo resuelto: A round trip
- Let $d$ be the one-way distance. Time is distance divided by rate: $\frac{d}{12}$ there and $\frac{d}{8}$ back.
- The times add: $\frac{d}{12} + \frac{d}{8} = 2.5$.
- Multiply every term by $24$: $2d + 3d = 60$, so $5d = 60$ and $d = 12$.
Respuesta: $12$ miles.
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