Because fractional exponents were defined to keep the exponent rules true, you can now use those rules on roots. Rewriting roots as powers often turns a messy radical problem into simple fraction arithmetic.
| Rule | Example with fractions |
|---|---|
| $x^a \cdot x^b = x^{a+b}$ | $x^{1/2} \cdot x^{1/3} = x^{5/6}$ |
| $\frac{x^a}{x^b} = x^{a-b}$ | $\frac{x^{3/4}}{x^{1/4}} = x^{1/2}$ |
| $(x^a)^b = x^{ab}$ | $\left(x^{2/3}\right)^{3/4} = x^{1/2}$ |
| $(xy)^a = x^a y^a$ | $\left(8x^6\right)^{1/3} = 2x^2$ |
Por qué funciona
Idea clave
Worked examples
Ejemplo resuelto: Roots of different index
- Rewrite: $x^{1/2} \cdot x^{1/3}$.
- Add the exponents: $\frac{1}{2} + \frac{1}{3} = \frac{3}{6} + \frac{2}{6} = \frac{5}{6}$.
Respuesta: $x^{5/6}$, which is $\sqrt[6]{x^5}$.
Ejemplo resuelto: Power of a product
- Apply the power to each factor: $16^{3/4} \cdot \left(x^8\right)^{3/4}$.
- $16^{3/4} = \left(\sqrt[4]{16}\right)^3 = 2^3 = 8$.
- $\left(x^8\right)^{3/4} = x^{8 \cdot 3/4} = x^6$.
Respuesta: $8x^6$
Ejemplo resuelto: A quotient
- Subtract the exponents: $\frac{5}{3} - \frac{1}{2} = \frac{10}{6} - \frac{3}{6} = \frac{7}{6}$.
Respuesta: $x^{7/6}$
Error común