Álgebra 2Rational Expressions and FunctionsA-APR.D.7

Multiplying and Dividing Rational Expressions

Factor everything, then multiply as with fractions.

Sin empezar Ir a la práctica

Esta lección aún no está traducida. Por ahora se muestra en inglés; la versión en español está en camino.

Multiplying and dividing rational expressions follows the rules for fractions: multiply straight across, and divide by multiplying by the reciprocal. The new habit from Simplifying Rational Expressions is to factor everything first, so you can cancel before anything gets big.

Idea clave

Factor every numerator and denominator. To divide, flip the second fraction and multiply. Cancel common factors anywhere between a numerator and a denominator, then multiply what is left. Excluded values include every $x$ that made any denominator 0, including the numerator of a fraction you flipped.

Por qué funciona

$\frac{a}{b} \cdot \frac{c}{d} = \frac{ac}{bd}$ is how fractions multiply, and dividing by $\frac{c}{d}$ means multiplying by $\frac{d}{c}$, because $\frac{c}{d} \cdot \frac{d}{c} = 1$. Cancelling before multiplying is allowed because multiplication can be done in any order. When you flip $\frac{c}{d}$, its numerator becomes a denominator, so values making $c = 0$ are excluded too.
$\frac{(x - 1)(x + 2)}{(x + 3)(x - 4)} \cdot \frac{x + 3}{x - 1}$ simplifies to $\frac{x + 2}{x - 4}$, but the cancelled factors leave holes at $x = 1$ and $x = -3$. The dashed line is the asymptote $x = 4$.

Worked examples

Ejemplo resuelto: Multiplying

Simplify $\frac{x^2 + x - 2}{x^2 - x - 12} \cdot \frac{x + 3}{x - 1}$.
  1. Factor: $\frac{(x - 1)(x + 2)}{(x + 3)(x - 4)} \cdot \frac{x + 3}{x - 1}$.
  2. Cancel $(x - 1)$ and $(x + 3)$.

Respuesta: $\frac{x + 2}{x - 4}$, for $x \ne 1, -3, 4$

Ejemplo resuelto: Dividing

Simplify $\frac{x^2 - 4}{3x} \div \frac{x + 2}{6x^2}$.
  1. Flip and multiply: $\frac{(x - 2)(x + 2)}{3x} \cdot \frac{6x^2}{x + 2}$.
  2. Cancel $(x + 2)$, and $\frac{6x^2}{3x} = 2x$.

Respuesta: $2x(x - 2)$, for $x \ne 0, -2$

Error común

Cancelling before you factor, for example crossing out the $x^2$ in $\frac{x^2 - 4}{x^2 + 2x}$. Terms inside a sum can't be cancelled. Factor first: $\frac{(x - 2)(x + 2)}{x(x + 2)} = \frac{x - 2}{x}$. Check with $x = 1$: $\frac{-3}{3} = -1$ and $\frac{-1}{1} = -1$.

Práctica

Apruebas con 3 respuestas correctas, las 2 últimas seguidas. Cada respuesta correcta da 2 XP.

Cargando la práctica…

Se apoya en

Lleva a

Fuentes y lecturas

  • OpenStax Intermediate Algebra 2e, Section 7.1 Multiply and Divide Rational Expressions
  • Common Core State Standards, A-APR.D.7