GeometríaRigid MotionsG-CO.A.2

Transformations as Functions

A transformation is a rule that sends each point to an image point.

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Esta lección aún no está traducida. Por ahora se muestra en inglés; la versión en español está en camino.

In Function Notation, a function takes an input and gives exactly one output. A transformation is a function whose inputs and outputs are points: it sends each point $P$ of the plane to an image point $T(P)$, usually written $P'$. The slides, turns and flips from Rotations and the enlargements from Dilations are all transformations.

Some transformations written as functions of the coordinates.
Rule $T(x, y)$What it doesKeeps every distance?
$(x + 3, y - 2)$translation: right 3, down 2yes
$(-x, y)$reflection over the $y$-axisyes
$(-y, x)$rotation $90^\circ$ counterclockwise about the originyes
$(2x, 2y)$dilation, scale factor 2, center the originno: all lengths double
$(x, 3y)$vertical stretchno: the shape changes too

Por qué funciona

A rigid motion is a transformation that keeps every distance the same: for any two points, $P'Q' = PQ$. Keeping distances keeps everything else too: side lengths, angle measures, area, straightness. To show a rule is not rigid, one pair of points whose distance changes is enough.
Try each transformation. Translations, reflections and rotations keep the triangle's size; a dilation changes it.

Idea clave

A transformation is a function on points: $T(P) = P'$. Rigid motions (translations, reflections, rotations) keep every distance and angle; dilations and stretches do not.

Ejemplo resuelto: Applying a rule

$T(x, y) = (y, -x)$. Find the images of $A(1, 2)$, $B(4, 2)$ and $C(1, 5)$.
  1. Put each point into the rule: the new $x$ is the old $y$; the new $y$ is the opposite of the old $x$.
  2. $A' = (2, -1)$, $B' = (2, -4)$, $C' = (5, -1)$.
  3. This rule turns the plane $90^\circ$ clockwise about the origin.

Respuesta: $A'(2, -1)$, $B'(2, -4)$, $C'(5, -1)$

Ejemplo resuelto: Is it rigid?

Is $T(x, y) = (2x, y)$ a rigid motion?
  1. Test two points: $A(0, 0)$ and $B(1, 1)$, with $AB = \sqrt{2}$.
  2. Images: $A' = (0, 0)$, $B' = (2, 1)$, so $A'B' = \sqrt{2^2 + 1^2} = \sqrt{5}$.
  3. $\sqrt{5} \ne \sqrt{2}$: the distance changed.

Respuesta: No. It stretches the plane sideways, so it is not rigid.

Ejemplo resuelto: Working backward

$T(x, y) = (x - 4, y + 1)$ and $T(P) = (2, 5)$. Find $P$.
  1. $T$ subtracts 4 from $x$ and adds 1 to $y$; undo both.
  2. $P = (2 + 4, 5 - 1) = (6, 4)$. Check: $T(6, 4) = (2, 5)$.

Respuesta: $P = (6, 4)$

Error común

Thinking any transformation that keeps the shape is rigid. A dilation keeps the shape but changes the size, so it is not rigid. A stretch like $(x, 3y)$ changes both size and shape. Check by computing one length before and after: a rigid motion never changes it.

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Fuentes y lecturas

  • OpenStax Contemporary Mathematics, 10.5 Tessellations (translations, rotations and reflections)
  • Common Core State Standards for Mathematics, High School Geometry, G-CO.A.2