Grado 6Fractions, Decimals and Factors6.NS.B.4

Factoring a Sum with the GCF

36 + 8 = 4(9 + 2).

Sin empezar Ir a la práctica

Esta lección aún no está traducida. Por ahora se muestra en inglés; la versión en español está en camino.

Once you can find the greatest common factor of two numbers, you can write their sum as one product. This is the distributive property used backward, and it is the same move you will soon make with letters.

Idea clave

To factor a sum, pull out the GCF and divide each number by it: $36 + 8 = 4(9 + 2)$, because $36 = 4 \times 9$ and $8 = 4 \times 2$.
A 4 by 9 rectangle and a 4 by 2 rectangle side by side make one 4 by 11 rectangle: $36 + 8 = 4(9 + 2)$.

Por qué funciona

Picture two rectangles with the same height, 4. One has area 36 (4 by 9), the other has area 8 (4 by 2). Push them together and you get one rectangle 4 tall and $9 + 2$ long. Its area is $4(9 + 2) = 44$, which is $36 + 8$. That is the distributive property: $4(9 + 2) = 4 \times 9 + 4 \times 2$.

Ejemplo resuelto: Pull out the GCF

Write $24 + 60$ as a product using the GCF.
  1. The GCF of 24 and 60 is 12.
  2. $24 = 12 \times 2$ and $60 = 12 \times 5$.
  3. So $24 + 60 = 12(2 + 5)$. Check: $12 \times 7 = 84$ and $24 + 60 = 84$.

Respuesta: $12(2 + 5)$

Ejemplo resuelto: With a letter

Factor $18 + 12x$.
  1. The GCF of 18 and 12 is 6.
  2. $18 = 6 \times 3$ and $12x = 6 \times 2x$.
  3. So $18 + 12x = 6(3 + 2x)$.

Respuesta: $6(3 + 2x)$

Error común

Pulling out a common factor that is not the greatest. $24 + 60 = 2(12 + 30)$ is true, but 12 and 30 still share a factor of 6, so it is not done. Quick check: the two numbers left inside the parentheses should have no common factor other than 1.

Práctica

Apruebas con 3 respuestas correctas, las 2 últimas seguidas. Cada respuesta correcta da 2 XP.

Cargando la práctica…

Se apoya en

Lleva a

Fuentes y lecturas

  • OpenStax, Prealgebra 2e, section 7.3 Distributive Property
  • Common Core State Standards for Mathematics, 6.NS.B.4: using the distributive property to factor a sum with a common factor