Grado 7Proportional Relationships7.RP.A.2a

Is It Proportional?

Every ratio y/x in the table is the same.

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Esta lección aún no está traducida. Por ahora se muestra en inglés; la versión en español está en camino.

You have built ratio tables: multiply both amounts by the same number and the ratio stays the same. A table like that shows a proportional relationship. Many tables look steady but are not proportional. Here is how to tell.

Idea clave

Two quantities are proportional when $\frac{y}{x}$ is the same number for every pair in the table. That number is the constant of proportionality.

Por qué funciona

Proportional means "scale one amount and the other scales the same way." If 2 tickets cost \$30, then 4 tickets (twice as many) cost \$60 (twice as much). This only works when every $y$ is the same multiple of its $x$, and that is the same as saying $\frac{y}{x}$ never changes. Adding a fixed amount breaks it: with $y = x + 3$, going from $x = 1$ to $x = 2$ doubles $x$ but takes $y$ from 4 to 5.
Each batch uses 2 cups of flour for 5 muffins. Try "What if we add instead?" to see why adding the same amount to both does not keep the ratio.

Worked examples

Ejemplo resuelto: A proportional table

Is pay proportional to hours? $$\begin{array}{l|ccc} \text{Hours} & 2 & 3 & 5 \\ \hline \text{Pay (dollars)} & 30 & 45 & 75 \end{array}$$
  1. Divide each pay by its hours: $\frac{30}{2} = 15$, $\frac{45}{3} = 15$, $\frac{75}{5} = 15$.
  2. Every quotient is 15, so pay is proportional to hours: \$15 for each hour.

Respuesta: Yes, proportional

Ejemplo resuelto: Steady, but not proportional

Is $y$ proportional to $x$? $$\begin{array}{l|cccc} x & 1 & 2 & 3 & 4 \\ \hline y & 4 & 5 & 6 & 7 \end{array}$$
  1. Divide: $\frac{4}{1} = 4$, $\frac{5}{2} = 2.5$, $\frac{6}{3} = 2$, $\frac{7}{4} = 1.75$.
  2. The quotients change, so it is not proportional. Here $y$ is always $x + 3$: the table adds, it does not multiply.

Respuesta: No, not proportional

Error común

Calling a table proportional because its values go up by the same amount each time. Steady growth is not enough. Check: divide $y$ by $x$ in at least two columns (all of them, to be sure). Another check: does $x = 0$ go with $y = 0$? For $y = x + 3$ it would go with $3$, so it is not proportional.

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Fuentes y lecturas

  • OpenStax, Prealgebra 2e, Section 6.5 Solve Proportions and their Applications
  • Common Core State Standards for Mathematics, 7.RP.A.2a