GeometríaArea, Volume and Modeling

Scaling Area and Volume

Scale lengths by k: areas scale by k², volumes by k³.

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Esta lección aún no está traducida. Por ahora se muestra en inglés; la versión en español está en camino.

Similar solids, like similar polygons in Similarity Through Transformations, have every length multiplied by the same scale factor $k$. Areas and volumes change by more, because they involve two or three lengths multiplied together. The formulas from Volume of Pyramids, Cones and Spheres show it.

Por qué funciona

Multiply every length of a box by $k$. Its surface area is made of products of two lengths, like $lw$, each of which becomes $(kl)(kw) = k^2 lw$: so area is multiplied by $k^2$. Its volume $lwh$ becomes $(kl)(kw)(kh) = k^3 lwh$. The same is true for any solid, since every area and volume formula multiplies two or three lengths.
A $2 \times 2 \times 2$ cube holds 8 unit cubes. Doubling every edge of a unit cube does not double its volume; it multiplies it by 8.

Idea clave

If lengths are scaled by $k$, areas (including surface area) are scaled by $k^2$ and volumes by $k^3$.

Ejemplo resuelto: Area and volume

A model car is built at a scale of $1 : 20$. The model's surface area is $150$ cm$^2$ and its volume is $400$ cm$^3$. Estimate the real car's surface area and volume.
  1. $k = 20$. Area: $20^2 \cdot 150 = 400 \cdot 150 = 60{,}000$ cm$^2$, which is $6$ m$^2$.
  2. Volume: $20^3 \cdot 400 = 8000 \cdot 400 = 3{,}200{,}000$ cm$^3$, which is $3.2$ m$^3$.

Respuesta: About $60{,}000$ cm$^2$ and $3{,}200{,}000$ cm$^3$

Ejemplo resuelto: Working backward

Two similar cylinders have volumes $54\pi$ and $250\pi$. The smaller one is $6$ cm tall. How tall is the larger one?
  1. Volume ratio: $\frac{250}{54} = \frac{125}{27} = k^3$, so $k = \frac{5}{3}$.
  2. Height: $6 \cdot \frac{5}{3} = 10$ cm.

Respuesta: $10$ cm

Ejemplo resuelto: Surface area from volume

Two similar solids have volumes in the ratio $8 : 27$. The smaller one has a surface area of $36$ in$^2$. Find the larger surface area.
  1. $k^3 = \frac{27}{8}$, so $k = \frac{3}{2}$, and $k^2 = \frac{9}{4}$.
  2. $36 \cdot \frac{9}{4} = 81$ in$^2$.

Respuesta: $81$ in$^2$

Error común

Doubling the volume when every length is doubled. If a box's length, width and height all double, its volume is $2 \cdot 2 \cdot 2 = 8$ times as large, and its surface area $4$ times as large. Check with unit cubes: a $2 \times 2 \times 2$ cube is made of 8 small ones.

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Fuentes y lecturas

  • OpenStax Contemporary Mathematics, 10.7 Volume and Surface Area
  • Common Core State Standards for Mathematics, High School Geometry, G-MG.A.1