Esta lección aún no está traducida. Por ahora se muestra en inglés; la versión en español está en camino.
Two figures are similar ($\sim$) if a sequence of rigid motions and dilations carries one onto the other. This builds on Congruence and Rigid Motions (rigid motions only) by also allowing a change of size, using the dilations of Properties of Dilations.
💡 Por qué funciona
Rigid motions keep lengths and angles. A dilation keeps angles and multiplies every length by the same $k$. So a similarity transformation keeps every angle and multiplies every length by one scale factor. For similar triangles $\triangle ABC \sim \triangle DEF$ that means: corresponding angles are congruent, and $\frac{DE}{AB} = \frac{EF}{BC} = \frac{FD}{CA} = k$.
A dilation followed by a rigid motion produces a similar figure: same angles, proportional sides.
🔑 Idea clave
Similar figures have congruent corresponding angles and proportional corresponding sides. The ratio of corresponding lengths is the scale factor, and it applies to every length, including perimeters.
✏️ Ejemplo resuelto: Finding a missing side
$\triangle ABC \sim \triangle DEF$ with $AB = 6$, $BC = 9$ and $DE = 10$. Find $EF$.
The scale factor from $ABC$ to $DEF$ is $\frac{DE}{AB} = \frac{10}{6} = \frac{5}{3}$.
$EF = \frac{5}{3} \cdot 9 = 15$.
Respuesta: $EF = 15$
✏️ Ejemplo resuelto: Describing the transformation
$\triangle ABC$ has $A(1, 1)$, $B(3, 1)$, $C(1, 2)$. $\triangle DEF$ has $D(-1, 4)$, $E(5, 4)$, $F(-1, 7)$. Describe a similarity transformation from $ABC$ to $DEF$.
Compare sides: $AB = 2$ and $DE = 6$; $AC = 1$ and $DF = 3$. Scale factor 3, and the shapes face the same way.
Dilate by 3 about the origin: $A \to (3, 3)$, $B \to (9, 3)$, $C \to (3, 6)$.
Each image is 4 left and 1 up from its target... check: $(3, 3) \to (-1, 4)$ is $\langle -4, 1 \rangle$. Translate by $\langle -4, 1 \rangle$: $B \to (5, 4)$, $C \to (-1, 7)$.
Respuesta: Dilate by 3 about the origin, then translate by $\langle -4, 1 \rangle$.
✏️ Ejemplo resuelto: Are all rectangles similar?
Are a $2 \times 3$ rectangle and a $4 \times 9$ rectangle similar?
All angles are $90^\circ$, so only the sides matter. Short sides: $\frac{4}{2} = 2$. Long sides: $\frac{9}{3} = 3$.
The ratios differ, so no single scale factor works.
Respuesta: No.
⚠️ Error común
Matching sides out of order. In $\triangle ABC \sim \triangle DEF$, side $\overline{AB}$ matches $\overline{DE}$ because of the letter order, just as with congruence. If you compare $AB$ with $EF$, you get a wrong scale factor. Check: in a scale factor larger than 1, every side of the bigger figure should be paired with a smaller side of the other.
Práctica
Apruebas con 3 respuestas correctas, las 2 últimas seguidas. Cada respuesta correcta da 2 XP.